x^2+45x+288=0

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Solution for x^2+45x+288=0 equation:



x^2+45x+288=0
a = 1; b = 45; c = +288;
Δ = b2-4ac
Δ = 452-4·1·288
Δ = 873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{873}=\sqrt{9*97}=\sqrt{9}*\sqrt{97}=3\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-3\sqrt{97}}{2*1}=\frac{-45-3\sqrt{97}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+3\sqrt{97}}{2*1}=\frac{-45+3\sqrt{97}}{2} $

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